SOLUTION: One solution contains 10% alcohol while another contains 30% alcohol. How many liters of each should be mixed to give 10 L of a solution 25% alcohol? Thanks!

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Question 344338: One solution contains 10% alcohol while another contains 30% alcohol. How many liters of each should be mixed to give 10 L of a solution 25% alcohol?
Thanks!
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Let A be the amount of 10% alcohol, B the amount of 30% alcohol.
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Total volume:
1.A%2BB=10
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Concentration of alcohol:
10A%2B30B=25%2810%29
2.A%2B3B=25
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Subtract eq. 1 from eq. 2,
A%2B3B-A-B=25-10
2B=15
highlight%28B=15%2F2%29L
Then from eq. 1,
A%2B15%2F2=10
A=20%2F2-15%2F2
highlight%28A=5%2F2%29L