Question 342739: How many liters of a 20% alcohol solution should Maria
mix with 50 liters of a 60% alcohol solution to obtain a
30% solution? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! How many liters of a 20% alcohol solution should Maria
mix with 50 liters of a 60% alcohol solution to obtain
a 30% solution?
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Equation:
alcohol + alcohol = alcohol
0.20x + 0.60*50 = 0.30(x+50)
Multiply thru by 100 to get:
20x + 60*50 = 30x + 30*50
10x = 30*50
x = 150 liters (amt. of 20% solution needed in the mixture)
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Cheers,
Stan H.
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