SOLUTION: How much water must be added to 20 liters of 50% antifreeze solution to reduce it to 40% antifreeze?

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Question 337439: How much water must be added to 20 liters of 50% antifreeze solution to reduce it to 40% antifreeze?
Found 2 solutions by Fombitz, nyc_function:
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Let A be the amount of 0% antifreeze (pure water).
50%2820%29%2B0%28A%29=40%2820%2BA%29
1000=800%2B40A
40A=200
A=5 liters

Answer by nyc_function(2741) About Me  (Show Source):
You can put this solution on YOUR website!
Let w = how much water must be added
w + 20(.50) = 0.40(w + 20)
Can you take it from here?