SOLUTION: a chem lab keeps 2 acids solutions on hand. one is 20% acid and the other is 35% acid. How much 20% and how much 35% acid solution should be used to prepare 25 liters of a 26% ac
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Question 333851: a chem lab keeps 2 acids solutions on hand. one is 20% acid and the other is 35% acid. How much 20% and how much 35% acid solution should be used to prepare 25 liters of a 26% acid solution? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! a chem lab keeps 2 acids solutions on hand. one is 20% acid and the other is 35% acid. How much 20% and how much 35% acid solution should be used to prepare 25 liters of a 26% acid solution?
Equations:
Quantity Eq.: x + y = 25
Acid Eq::::0.20x + 0.35y = 0.26*25
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Multiply thru the Quantity Eq. by 20
Multiply thru the Acid Eq by 100
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20x + 20y = 20*25
20x + 35y = 26*25
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Subtract 1st from 2nd to get:
15y = 6*25
y = 10 liters (amt. of 35% solution in the mixture.
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x = 25-y = 15 liters (amt. 20% solution in the mixture.
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Cheers,
Stan H.
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