SOLUTION: how many ounces of an alloy containing 30% gold on the world market must be mixed with an alloy containing 5% gold to obtain 25 ounces of an alloy containing 20% gold?
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Question 327704: how many ounces of an alloy containing 30% gold on the world market must be mixed with an alloy containing 5% gold to obtain 25 ounces of an alloy containing 20% gold? Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! how many ounces of an alloy containing 30% gold on the world market must be mixed
with an alloy containing 5% gold to obtain 25 ounces of an alloy containing 20% gold?
:
Let x = amt of 30% alloy
The resulting total is to be 25 oz, therefore:
(25-x) = amt of 5% alloy
:
A typical mixture equation:
.30x + .05(25-x) = .20(25)
.30x + 1.25 - .05x = 5
.30x - .05x = 5 - 1.25
.25x = 3.75
x =
x = 15 oz of 30% alloy required
then
25-15 = 10 oz of 5% alloy
:
:
Check solution
.30(15) + .05(10) = .20(25)
4.5 + .5 = 5
