SOLUTION: How many liters of a 45% acid solution must be added to 15 liters of a 30% acid solution to produce a 35% acid solution?
I tried 45%(x) + 30%*(15-x)= (35%)(15)
.45+.30(15-x)=(
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I tried 45%(x) + 30%*(15-x)= (35%)(15)
.45+.30(15-x)=(
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Question 320658: How many liters of a 45% acid solution must be added to 15 liters of a 30% acid solution to produce a 35% acid solution?
I tried 45%(x) + 30%*(15-x)= (35%)(15)
.45+.30(15-x)=(.35)(15)
.45x + 4.5 -.30x+ 5.25
.15x +4.5 = 5.25
-4.5 = -4.5
.75/.15 = 5% answer
Thank you; Word problems are definitely my weakness in understanding and setting up.
You can put this solution on YOUR website! How many liters of a 45% acid solution must be added to 15 liters of a 30% acid solution to produce a 35% acid solution?
:
I'm not sure what you are doing here, but let's think this out.
:
Let x = amt of 45% solution to be added
then we know the resulting mixture will be (x+15), right?
Use the decimal equiv, write a typical mixture equation
:
.45x + .30(15) = .35(x+15)
:
.45x + 4.5 = .35x + 5.25
:
.45x - .35x = 5.25 - 4.5
:
.10x = .75
x =
x = 7.5 liters to be added
:
:
Check this in the original equation
.45(7.5) + .30(15) = .35(7.5+15)
3.375 + 4.5 = .35(22.5)
7.875 = 7.875; confirms our solution
:
did this make sense to you?
