SOLUTION: John is traveling to a meeting that is 28 miles away. He needs to be there in 30 minutes. How fast does he need to go to make it to the meeting on time?

Algebra ->  Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: John is traveling to a meeting that is 28 miles away. He needs to be there in 30 minutes. How fast does he need to go to make it to the meeting on time?      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 315387: John is traveling to a meeting that is 28 miles away. He needs to be there in 30 minutes. How fast does he need to go to make it to the meeting on time?
Found 2 solutions by rfer, jim_thompson5910:
Answer by rfer(16322) About Me  (Show Source):
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Use the equation d=rt where d is the distance, r is the speed, and t is the time.

So we're given that "a meeting that is 28 miles away. He needs to be there in 30 minutes.", which means that d=28 and t=0.5 (30 minutes = 0.5 hours). Plug these values in to get:

28=r%280.5%29

Now divide both sides by 0.5 and flip the equation to get r=56. So John needs to go 56 mph to go 28 miles in 30 minutes.