SOLUTION: 62(200 Solution A is 80% Alcohol and Solution B is 30% Alcohol. How many Liters of each Solutions should be mixed in order to make 200 liters of a Solution that is 62% Alcohol ?

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Question 313284: 62(200
Solution A is 80% Alcohol and Solution B is 30% Alcohol. How many Liters of each Solutions should be mixed in order to make 200 liters of a Solution that is 62% Alcohol ?
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
1.80A%2B30B=62%28200%29
2.A%2BB=200
Multiply eq.2 by -30 and add the equations together.
80A%2B30B-30A-30B=62%28200%29-30%28200%29
50A=32%28200%29
A=32%284%29
highlight%28+A-128%29
Then from eq. 2,
128%2BB=200
highlight%28+B=72%29
128 liters of 80% solution and 72% of the 30% solution.