Question 311423: One liter of 70% alcohol is needed. How much of 95% alcohol could be used to satisfy the 70% originally required? Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! Assuming it's diluted with something with no alcohol:
1 liter of 70% --> 0.7 liters of alcohol
0.7/0.95 =~ 0.7368 liters of 95% + 0.2602 liters of dilutant (water or tonic water)