Question 310828: How much water must be added to 300ML of a 60% acid solution in order to dilute it to a solution of 45% acids? Found 2 solutions by stanbon, modi.kk91:Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! How much water must be added to 300ML of a 60% acid solution in order to dilute it to a solution of 45% acids?
Equation:
acid + acid = acid
0.60*300 + 0*x = 0.45(300+x)
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Multiply thru by 100 to get:
60*300 + 0 = 45*300 + 45x
45x = 15*300
x = (1/3)(300)
x = 100 ML (amt. of water that must be added to the mix)
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Cheers,
Stan H.
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