SOLUTION: How many liters of a 10% alcohol solution must be mixed with 50 liters of a 80% solution to get a 20% solution?

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Question 310597: How many liters of a 10% alcohol solution must be mixed with 50 liters of a 80% solution
to get a 20% solution?
Found 2 solutions by Fombitz, modi.kk91:
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Let X be the liters of 10% solution.
10%28X%29%2B80%2850%29=20%28X%2B50%29
10X%2B4000=20X%2B1000
-10X=-3000
X=300
300 liters of 10% solution.

Answer by modi.kk91(20) About Me  (Show Source):
You can put this solution on YOUR website!

10% 80%


20%

80-20=60 20-10=10
ratio=6:1

6:1::x:50


x=300liter