SOLUTION: Will you please assist me on these two algebraic solution: -9x + 5/7= 7/9. 2/5 (10x-3) -x=9/5. 1. This is how I start the first one: -9x + 5/7= 7/9 -9x +5/7-5/7 = 7/9-5/7=

Algebra ->  Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: Will you please assist me on these two algebraic solution: -9x + 5/7= 7/9. 2/5 (10x-3) -x=9/5. 1. This is how I start the first one: -9x + 5/7= 7/9 -9x +5/7-5/7 = 7/9-5/7=       Log On

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Question 309203: Will you please assist me on these two algebraic solution:
-9x + 5/7= 7/9.
2/5 (10x-3) -x=9/5.
1. This is how I start the first one: -9x + 5/7= 7/9
-9x +5/7-5/7 = 7/9-5/7= 4/63 reduce it to 36/63 and still wrong.
2. 2/5 (10x-3)-x=9/5
2/5 (7x)-x=9/5
2/5x 7x-x=9/5
2/5 x 6x=9/5
2/5 x 6/1=12/5 =9/5
lose at this point.

Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!










And here is your problem. You multiplied by 9 instead of dividing by -9.



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You said BUZZ!!! Sorry, that is incorrect. You can't combine unlike terms. 10x has an x, 3 doesn't. That makes the terms unlike. Game over, but thank you for playing.

First, distribute the



Then collect terms:







John