You can put this solution on YOUR website! a chemist has 6 liters of a 50% acid solution.
how much water must be added to obtain a 20% acid solution?
:
Let x = amt of water required
:
A simple "amt of acid" equation
:
.50(6) = .20(x+6)
3 = .2x + 1.2
3 - 1.2 = .2x
1.8 = .2x
x =
x = 9 liters of water required
:
:
Check to see if the amt of acid remains the same (only the % changes)
.50(6) = .2(9+6)
3 = 3