SOLUTION: 7. A 25% solution of alcohol is to mixed with a 40% solution to get 50 litres of a final mixture that is 30% alcohol. How much of each of the original s

Algebra ->  Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: 7. A 25% solution of alcohol is to mixed with a 40% solution to get 50 litres of a final mixture that is 30% alcohol. How much of each of the original s      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 299719: 7. A 25% solution of alcohol is to mixed with a 40% solution to get 50 litres of a final mixture that is 30% alcohol. How much of each of the original solutions should be used?
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
.40X+.25(50-X)=.30*50
.40X+12.5-.25X=15
.15X=15-12.5
.15X=2.5
X=2.5/.15
X=16.667 LITERS OF TH4 40% MIXTURE IS USED.
50=16.666=33.333 LITERS OF THE 25% MIXTURE IS USED.
PROOF:
.40*16.667+.25*33.333=.30*50
6.667+8.333=15
15=15