Question 290381: a chemist mixes 12 L of a solution that is 45% acid with 8 L of a solution that is 70% acid. What is the percent of acid of the mixture? Found 3 solutions by brucewill, amalm06, ikleyn:Answer by brucewill(101) (Show Source):
You can put this solution on YOUR website! This isn't exactly an algebraic solution, it's just logic.
12 L * .45 = 5.4 L of pure acid
8 L * .70 = 5.6 L of pure acid.
There are 11 L of acid, in 20 L of liquid, therefore, it would be 55% acid solution. (11/20).
You can put this solution on YOUR website! In this question, you are increasing the amount (concentration) of acid. The final concentration should be between 45% and 70%.
x=[(70-45)/45]x100=55% (Answer)
The percent of acid in the mixture = = 0.55 = 55%.
The numerator of the fraction is the pure acid content in liters, coming from two ingredients.
The denominator is the total liquid volume, in liters.
You will find there ALL TYPICAL mixture problems with different methods of solutions,
explained at different levels of detalization, from very detailed to very short.
Read them and become an expert in solution mixture word problems.
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