SOLUTION: Soybean meal is 16% protein. Corn meal is 10% protein. How much of each type should be mixed to bet a 15-lb mixture that is 12% protein?

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Question 27934: Soybean meal is 16% protein. Corn meal is 10% protein. How much of each type should be mixed to bet a 15-lb mixture that is 12% protein?
Found 2 solutions by Paul, Earlsdon:
Answer by Paul(988) About Me  (Show Source):
You can put this solution on YOUR website!
0.16x+0.1(15-x)=0.12(15)
0.16x+1.5-0.1x=1.8
0.06x=0.3
x=5

15-5=10

Hence, for 16% it is 50lb and for 10% it is 10-lb.
Paul.

Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Let x = the required number of pounds of 16%-protein soybean meal
15-x = the required number of pounds of 10%-protein corn meal.
You want x lbs of 16%-protein (0.16x) plus (15-x) lbs of 0.10%-protein (0.10(15-x)) to equal 15 lbs of 12% (0.12)(15) of mixture.
Change the percents to their eqivalent decimals and write the equation.
0.16x+%2B+0.10%2815-x%29+=+0.12%2815%29 Simplify and solve for x.
0.16x+%2B+1.5+-+0.1x+=+1.8 Combine the x-terms.
0.06x+%2B+1.5+=+1.8 Subtract 1.5 from both sides of the equation.
0.06x+=+0.3 Divide both sides by 0.06
x+=+5
You will need 5 lbs of 16%-protein soybean meal and 10 lbs of 10%-protein corn meal to make a 15-lb mixture that is 12% protein.