SOLUTION: Train A is traveling at 100 miles per hour, and train b is traveling at 104 miles per hour/ Train A passes the station at 4:25 a.m and train B passes the station at 4:55 a.m. What
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Question 278076: Train A is traveling at 100 miles per hour, and train b is traveling at 104 miles per hour/ Train A passes the station at 4:25 a.m and train B passes the station at 4:55 a.m. What time will train B catch up to train A? Found 2 solutions by ankor@dixie-net.com, Alan3354:Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! Train A is traveling at 100 miles per hour, and train b is traveling at 104 miles per hour/
Train A passes the station at 4:25 a.m and train B passes the station at 4:55 a.m.
What time will train B catch up to train A?
:
from the given information, we know that train B is 30 min (1/2 hr) behind
train A, when train A passes the station
:
The distance between the trains at this time: * 104 = 52 mi
:
Let t = time required for train B to catch train A
:
write a distance equation: Dist = speed * time
:
Train B travel dist = Train A travel dist + 52 mi
104t = 100t + 52
104t - 100t = 52
4t = 52
t =
t = 13 hrs
:
4:25 am + 13:00 = 5:25 pm, B catches A
You can put this solution on YOUR website! Train A is traveling at 100 miles per hour, and train b is traveling at 104 miles per hour/ Train A passes the station at 4:25 a.m and train B passes the station at 4:55 a.m. What time will train B catch up to train A?
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Train A goes 50 miles from 525 to 455 (100 mph x 1/2 hour)
Train B gains on train A at 4 mph (104 - 100)
50 miles/4 mph = 12.5 hours
0455 + 12.5 = 5:25 PM the same day
