Question 276530: How many ounces of a 20% saline solution must be added to 40 ounces of a 10% solution to produce a 16% solution? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! How many ounces of a 20% saline solution must be added to 40 ounces of a 10% solution to produce a 16% solution?
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One-variable solution:
Equation:
0.20x + 0.10*40 = 0.16(x+40)
Multiply thru by 100 to get:
20x + 10*40 = 16x + 16*40
4x = 6*40
x = 6*10
x = 60 oz (amt of 20% solution needed in for the mixture)
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Cheers,
Stan H.
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