SOLUTION: For wat intergral values of n is the expression 1n + 2n + 3n + 4n divisible by 5? *note n values are writen in superscript*

Algebra ->  Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: For wat intergral values of n is the expression 1n + 2n + 3n + 4n divisible by 5? *note n values are writen in superscript*      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 26893: For wat intergral values of n is the expression 1n + 2n + 3n + 4n divisible by 5?
*note n values are writen in superscript*
Answer by 303795(602) About Me  (Show Source):
You can put this solution on YOUR website!
1%5En+%2B+2%5En++%2B+3%5En++%2B+4%5En+
Whenever n is divisible by 4 the last digit of the total ends in 4. This number can not be divided by 5.
All other values of n end in 0. This is therefore divisible by 5.
Note n must be positive.
n Total
1 10
2 30
3 100
4 354
5 1300
6 4890
7 18700
8 72354
9 282340
10 1108650
11 4373500
12 17312754
13 68711380
14 273234810
15 1088123500