You can put this solution on YOUR website! how many quarts of pure antifreeze must be added to 4 quarts of a 10% antifreeze solution to obtain a 20% antifreeze solution?
:
Let x = amt of pure antifreeze required
:
Write a decimal equiv mixture equation (pure antifreeze is 100% or 1x)
.10(4) + x = .20(x + 4)
.4 + x = .2x + .8
x - .2x = .8 - .4
.8x = .4
x =
x = .5, half a quart of pure antifreeze required