SOLUTION: How many liters of 100% pure acid should be added to 22 liters of a 30% acid solution to obtain a 45% acid solution?

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Question 264399: How many liters of 100% pure acid should be added to 22 liters of a 30% acid solution to obtain a 45% acid solution?
Answer by drk(1908) About Me  (Show Source):
You can put this solution on YOUR website!
This is a mixture problem. Here is a table based on the given information.
acids . . . . . . .% . . . . . . . . .L . . . . . . . . .#L
pure. . . . . . . 100. . . . . . . x. . . . . . . . .100x
30. . . . . . . . . 30 . . . . . . . 22. . . . . . . .660
mixture. . . . . 45 . . . . . . .22+x . . . . . .990 + 45x
looking at the third column, we get
100x+%2B+660+=+990+%2B+45x
subtract 660 and subtract 45x to get
55x+=+330
divide to get
x+=+6 liters