SOLUTION: A butcher has some hamburger that is 29% fat and some that is 15% fat. How many pounds of each should be mixed to make 63 lb of hamburger that is 17% fat?

Algebra ->  Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: A butcher has some hamburger that is 29% fat and some that is 15% fat. How many pounds of each should be mixed to make 63 lb of hamburger that is 17% fat?      Log On

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Question 263426: A butcher has some hamburger that is 29% fat and some that is 15% fat. How many pounds of each should be mixed to make 63 lb of hamburger that is 17% fat?
Found 2 solutions by richwmiller, drk:
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
.29x+.15(63-x)=.17*63
solve for x amd 63-x

Answer by drk(1908) About Me  (Show Source):
You can put this solution on YOUR website!
This is a mixture problem. Here is a table based on the given information
fat . . . . . . .% . . . . . . pounds . . . . . . . . %-pounds
29. . . . . . . 29 . . . . . . . .p . . . . . . . . . . .29p
15 . . . . . . .15 . . . . . . . .63-p. . . . . . . . .945 -15p
17 . . . . . . .17 . . . . . . . .63. . . . . . . . . . .1071
set the third column equal to get
29p+%2B+945+-+15p+=+1071
combine like terms to get
14p+%2B+945+=+1071
subtract 945 to get
14p+=+126
p = 9 pounds @ 29 %
63-p = 54 pounds @ 15%