SOLUTION: A candy store sells boxes of candy containing caramels and cremes. Each box sells for $12.50 and holds 30 pieces of candy (all pieces are the same size). If the caramels cost $0.25
Algebra ->
Customizable Word Problem Solvers
-> Mixtures
-> SOLUTION: A candy store sells boxes of candy containing caramels and cremes. Each box sells for $12.50 and holds 30 pieces of candy (all pieces are the same size). If the caramels cost $0.25
Log On
Question 261969: A candy store sells boxes of candy containing caramels and cremes. Each box sells for $12.50 and holds 30 pieces of candy (all pieces are the same size). If the caramels cost $0.25 to produce and the cremes cost $0.45 to produce, how many of each should be in a box to make a profit of $3? Answer by drk(1908) (Show Source):
You can put this solution on YOUR website! we have two equations here:
(i)
(ii)
--
we have a profit of $3. If we sell a box for $12.50 and our profit is $3.00
the cost to us is $9.50
---
multiply (i) by -25 to get
(iii)
add (ii) and (iii) to get
(iv)
So,
creme = 8 and caramel = 22
--