SOLUTION: A candy store sells boxes of candy containing caramels and cremes. Each box sells for $12.50 and holds 30 pieces of candy (all pieces are the same size). If the caramels cost $0.25

Algebra ->  Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: A candy store sells boxes of candy containing caramels and cremes. Each box sells for $12.50 and holds 30 pieces of candy (all pieces are the same size). If the caramels cost $0.25      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 261969: A candy store sells boxes of candy containing caramels and cremes. Each box sells for $12.50 and holds 30 pieces of candy (all pieces are the same size). If the caramels cost $0.25 to produce and the cremes cost $0.45 to produce, how many of each should be in a box to make a profit of $3?
Answer by drk(1908) About Me  (Show Source):
You can put this solution on YOUR website!
we have two equations here:
(i) Ca+%2B+Cr+=+30
(ii) 25Ca+%2B+45Cr+=+950
--
we have a profit of $3. If we sell a box for $12.50 and our profit is $3.00
the cost to us is $9.50
---
multiply (i) by -25 to get
(iii) -25Ca+-+25Cr+=+-750
add (ii) and (iii) to get
(iv) 20Cr+=+200
So,
creme = 8 and caramel = 22
--