SOLUTION: A photographer is mixing 5% acetic acid solution with a 10% acetic acid solution to get 2 liters of a 7% solution. How many liters of each solution should he add?

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Question 258810: A photographer is mixing 5% acetic acid solution with a 10% acetic acid solution to get 2 liters of a 7% solution. How many liters of each solution should he add?
Found 2 solutions by CharlesG2, Fombitz:
Answer by CharlesG2(834) (Show Source):
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A photographer is mixing 5% acetic acid solution with a 10% acetic acid solution to get 2 liters of a 7% solution. How many liters of each solution should he add?

5% solution X, 10% solution Y
X+Y=2 --> X=2-Y
0.07*2 liters = 0.14 liters acetic acid
0.05(2-Y) + 0.10Y = 0.14
0.10 - 0.05Y + 0.10Y = 0.14
0.10 + 0.05Y = 0.14
0.05Y = 0.04
Y=0.04/0.05=4/5=0.8 liters of 10% ascetic acid solution
and since X+Y=2
we will need 1.2 liters of the 5% and 0.8 liters of the 10%

Answer by Fombitz(32388) (Show Source):
You can put this solution on YOUR website!
F-liters of 5% solution
T-liters of 10% solution
1.Volume equation:
2.Concentration equation:
Use eq. 1 to solve for F in terms of T and substitute into eq.2,

2.

Then from eq. 1,

Use 4/5 liter of 5% solution and 6/5 liter of 10% solution.