SOLUTION: A beaker contains a solution that is 15% alcohol. In another beaker is a solution that is 40% alcohol. How mcuh of each should be mixed to obtain 9 L of solution that is 25% alco
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Question 243145: A beaker contains a solution that is 15% alcohol. In another beaker is a solution that is 40% alcohol. How mcuh of each should be mixed to obtain 9 L of solution that is 25% alcohol? Answer by checkley77(12844) (Show Source):
You can put this solution on YOUR website! .40x+.15(9-x)=.25*9
.40x+1.35-.15x=2.25
.25x=2.25-1.35
.25x=.9
x=.9/.25
x=3.6 L of 40% solution is used.
9-3.6=5.4 L of 15% solution is used.
Proof:
.40*3.6+.15*5.4=2.25
1.44+.81=2.25
2.25=2.25
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