Question 222574: how much water should be added to 1 gallon of pure antifreeze to obtain a solution of 95% antifreeze?
Found 2 solutions by nerdybill, RAY100:
Answer by nerdybill(7384)   (Show Source):
You can put this solution on YOUR website! how much water should be added to 1 gallon of pure antifreeze to obtain a solution of 95% antifreeze?
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Let x = gallons of water added
then
1 = .95(1+x)
1 = .95+.95x
.05 = .95x
.05/.95 = x
.0526 gallons = x (amount of water to add)
Answer by RAY100(1637)  (Show Source):
You can put this solution on YOUR website! Let x = amt of pure water added (0% antifreeze)
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(0 %) x + 1(100%) = (1+x)(95%)
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0*x + 1+1.00 = .95 +.95x
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1=.95 +.95x
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.05 = .95x
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.053 = x,,,, in gallons
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Check
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0(.053) +1 = .95(1.053)= 1,,,,,ok
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