SOLUTION: A ladder is resting against a wall. The top of the ladder touches the wall at a height of 9ft. Find the length of the ladder if the length is 3ft more than its distance from the wa

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Question 218246: A ladder is resting against a wall. The top of the ladder touches the wall at a height of 9ft. Find the length of the ladder if the length is 3ft more than its distance from the wall.

Found 2 solutions by RAY100, drj:
Answer by RAY100(1637) About Me  (Show Source):
You can put this solution on YOUR website!
Let d=distance from wall in ft
.
ladder is then (d+3) long in feet
.
We now have a right triangle with legs,,9,,and d,,,,with hypotenuse (d+3)
.
Using the Pythagorean Theorem,,c^2 =a^2 + b^2,,,
.
(d+3)^2 = d^2 +9^2
.
d^2 +6d +9 = d^2 +81
.
6d = 72
.
d=12 ft,,,,ladder is 12+3 = 15 ft
.
checking ,,,,9^2 +12^2 = 81 +144 =225 = 15^2,,,,ok
.

Answer by drj(1380) About Me  (Show Source):
You can put this solution on YOUR website!
A ladder is resting against a wall. The top of the ladder touches the wall at a height of 9ft. Find the length of the ladder if the length is 3ft more than its distance from the wall.

Step 1. Let h=9 be the height the ladder touches the wall.

Step 2. Let d=3 ft be the distance from wall

Step 3. Let L be the length of the ladder and L=3+d since length is 3 ft more than d.

Step 4. We can use the Pythagorean Theorem for a right triangle which states that the sum of the squares of the legs (h and d) is the number of the squares of the hypotenuse or L in this case. That is,

L%5E2=h%5E2%2Bd%5E2

%28d%2B3%29%5E2=9%5E2%2Bd%5E2=81%2Bd%5E2

d%5E2%2B6d%2B3%5E2=81%2Bd%5E2

6d%2B9=81

Subtract 9 from both sides of the equation

6d%2B9-9=81-9

6d=72

Divide 6 to both sides of the equation

6d%2F6=72%2F6

d=12 and d%2B3=15

Step 5. ANSWER: The length of the ladder is 15 feet.

I hope the above steps were helpful.

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And good luck in your studies!

Respectfully,
Dr J

drjctu@gmail.com

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