Question 217064: A lab has a 20% acid solution and a 50% acid solution. How many liters of each are required to obtain 600 liters of a 30% acid solution? Answer by nerdybill(7384) (Show Source):
You can put this solution on YOUR website! A lab has a 20% acid solution and a 50% acid solution. How many liters of each are required to obtain 600 liters of a 30% acid solution?
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Let x = liters of 20% acid solution
then
600-x = liters of 50% acid solution
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.20x + .50(600-x) = .30(600)
.20x + 300 - .50x = 180
300 - .30x = 180
300 = .30x + 180
120 = .30x
400 liters = x (amount of 20% acid solution)
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Amount of 50% acid solution:
600-x = 600-400 = 200 liters
