Question 213388: how many gallons of pure alcohol should b mixed with 20 gallons of a 15% alchol solution to obtain a mixture that is 25% alcohol?
Found 2 solutions by stanbon, RAY100:
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! how many gallons of pure alcohol should be mixed with 20 gallons of a 15% alcohol solution to obtain a mixture that is 25% alcohol?
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alcohol + alcohol = alcohol
0.15*20 + x = 0.25(20+x)
Multiply thru by 100 to get:
15*20 + 100x = 25*20 + 25x
75x = 10*20
x = 2 2/3 gallons (amount of 100% alcohol needed for the mixture)
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Cheers,
Stan H.
Answer by RAY100(1637) (Show Source):
You can put this solution on YOUR website! Let x = gallons of pure(100%) alcohol added
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x(1.00) +20(.15) = (20 +x)(.25)
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x+3=5+.25x,,,,,,,,,alcohol balance
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,75 x = 2
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x=2.67 gallons
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check,,,2.67 +3 = 22.67 * .25 = 5.67,,,,,ok
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