SOLUTION: Train A and B are traveling in the same direction on parallel tracks. Train A is traveling at 100 miles per hour and train B is traveling at 120 miles per hour. Train A passes a st

Algebra ->  Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: Train A and B are traveling in the same direction on parallel tracks. Train A is traveling at 100 miles per hour and train B is traveling at 120 miles per hour. Train A passes a st      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 199857: Train A and B are traveling in the same direction on parallel tracks. Train A is traveling at 100 miles per hour and train B is traveling at 120 miles per hour. Train A passes a station at 2:25 A.M.. If train B passes the same station at 2:40 A.M. at what time will train B catch up to train A?
When will train B catch up to train A?

Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
Train A and B are traveling in the same direction on parallel tracks.
Train A is traveling at 100 miles per hour and train B is traveling at 120 miles per hour.
Train A passes a station at 2:25 A.M.. If train B passes the same station at
2:40 A.M. at what time will train B catch up to train A?
When will train B catch up to train A?
:
Find the distance that train B is behind train A at 2:25
Train B is 15 min (which is.25 hr), from train A at that time.
120 * .25 = 30 mi
:
Relative speed between the two trains: 120 - 100 = 20 mph
:
How long will it take to cover 30 mi at 20 mph?
Time = 30%2F20 = 1.5 hrs
:
Train B catches Train A: 2:25 + 1:30 = 3:55 AM
:
:
Check solution by finding the distance traveled by each train in 1.5 hrs:
120 * 1.5 = 180 mi
100 * 1.5 = 150 mi
--------------------
difference = 30 mi
:
:
Did all this make sense to you?