SOLUTION: 9 Ibs. of mixed nuts containing 55% peanutes were mixed with 6Ibs of another kind of mixed nuts that contain 40% peanuts. What percent of the new mixture is peanuts?

Algebra ->  Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: 9 Ibs. of mixed nuts containing 55% peanutes were mixed with 6Ibs of another kind of mixed nuts that contain 40% peanuts. What percent of the new mixture is peanuts?      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 198752: 9 Ibs. of mixed nuts containing 55% peanutes were mixed with 6Ibs of another kind of mixed nuts that contain 40% peanuts. What percent of the new mixture is peanuts?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
In words:
(lbs of peanuts in final mixture)/(total pounds of mixture) = (% peanuts)
9%2A.55+=+4.95 lbs
6%2A.4+=+2.4 lbs
%284.95+%2B+2.4%29%2F%289+%2B+6%29
7.35%2F15+=+.49
The new mixture is 49% peanuts