SOLUTION: Brand X sells 21 oz. bags of mixed nuts that contain 29% peanuts. To make their product they combine Brand A mixed nuts which contain 35% peanuts and Brand B mixed nuts which c

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Question 198078: Brand X sells 21 oz. bags of mixed nuts that
contain 29% peanuts. To make their
product they combine Brand A mixed nuts
which contain 35% peanuts and Brand B
mixed nuts which contain 25% peanuts.
How much of each do they need to use?

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let a= ounces of brand A nuts used
Let b= ounces of brand B nuts used
In words:
(ounces of peanuts in final mixture)/(total ounces of mixture) = 29%
%28.35a+%2B+.25b%29+%2F+21+=+.29
.35a+%2B+.25b+=+.29%2A21
(1) .35a+%2B+.25b+=+6.09
(2) a+%2B+b+=+21
Multiply both sides of (2) by .25 and
subtract (2) from (1)
(1) .35a+%2B+.25b+=+6.09
(2) -.25a+-+.25b+=+-5.25
-----------------------------
.1a+=+.84
a+=+8.4
and, since
a+%2B+b+=+21
8.4+%2B+b+=+21
b+=+21+-+8.4
b+=+12.6
8.4 ounces of brand A and 12.6 ounces of brand B are needed
check:
%28.35a+%2B+.25b%29+%2F+21+=+.29
%28.35%2A8.4+%2B+.25%2A12.6%29+%2F+21+=+.29
%282.94+%2B+3.15%29+%2F+21+=+.29
6.09%2F21+=+.29
.29+=+.29
OK