SOLUTION: In a chemistry class, 9 liters of a 4% silver iodide solution must be mixed with a 10% solution to get a 6% solution. How many liters of the 10% solution are needed?

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Question 195320: In a chemistry class, 9 liters of a 4% silver iodide solution must be mixed with a 10% solution to get a 6% solution. How many liters of the 10% solution are needed?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let x= liters of 10% solution needed
In words:
(liters of silver iodide)/(total liters of solution) = 6%
%28.04%2A9+%2B+.1x%29+%2F+%289+%2B+x%29+=+.06
Multiply both sides by 9+%2B+x
.36+%2B+.1x+=+.06%2A%289+%2B+x%29
.36+%2B+.1x+=+.54+%2B+.06x
.04x+=+.18
x+=+4.5
4.5 liters of the 10% solution are needed
check:
%28.04%2A9+%2B+.1x%29+%2F+%289+%2B+x%29+=+.06
%28.04%2A9+%2B+.1%2A4.5%29+%2F+%289+%2B+4.5%29+=+.06
%28.36+%2B+.45%29+%2F13.5+=+.06
.81%2F13.5+=+.06
.06+=+.06
OK