SOLUTION: A chemist wishes to mix some pure acid with a 10% solution to obtain 60 liters of a 20% acid solution. How many liters of each of the original solutions are needed?
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Question 170499: A chemist wishes to mix some pure acid with a 10% solution to obtain 60 liters of a 20% acid solution. How many liters of each of the original solutions are needed?
I know I need to set up a chart and have two equations but I am really stuck on this one. Answer by Mathtut(3670) (Show Source):
You can put this solution on YOUR website! lets call amount of 10% solution x and the amount of pure acid y.
:
x+y=60..eq 1
.1x+1y=.2(60)..eq 2
:
multiply eq 2 by -1 and subtract from eq 1 to eliminate the y terms
:
.9x=48
: amount of 10% solution amount of pure acid
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