SOLUTION: trains a and b are traveling in the same direction on parallel tracks, train a is traveling at 80 miles per hour, and train b is traveling at 100 miles per hour, train a passes a s
Algebra ->
Customizable Word Problem Solvers
-> Mixtures
-> SOLUTION: trains a and b are traveling in the same direction on parallel tracks, train a is traveling at 80 miles per hour, and train b is traveling at 100 miles per hour, train a passes a s
Log On
Question 169166: trains a and b are traveling in the same direction on parallel tracks, train a is traveling at 80 miles per hour, and train b is traveling at 100 miles per hour, train a passes a station at 9:10 a.m. if train b passes the same station at 9:25 a.m. at what time will train b catch up to train a. Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! trains a and b are traveling in the same direction on parallel tracks,
train a is traveling at 80 miles per hour, and
train b is traveling at 100 miles per hour,
train a passes a station at 9:10 a.m.
if train b passes the same station at 9:25 a.m. at what time will train b catch up to train a.
:
At 9:10, train b is 15 min(.25 hr) from the station
:
At 100 mph that would be .25(100) = 25 mi from the station and from train a
:
The relative speed of the two trains: 100 - 80 = 20 mph
;
How long will it take train b to travel 25 mi at 20 mph
: = 1.25 hrs or 1 hr 15 min from 9:10 = 10:25 am, train b passes train a
:
We can check that by finding the dist traveled by both trains
Train a: 1.25(80) = 100 mi
Train b: 1.25(100) = 125 mi. (It started 25 mi behind train a)
:
Did this make sense?
