SOLUTION: Working on Chemistry homework. Could not understand this problem in class, still don't understand. "The density of an antifreeze soltuion measured .78g/ml. The solution was a mixtu

Algebra ->  Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: Working on Chemistry homework. Could not understand this problem in class, still don't understand. "The density of an antifreeze soltuion measured .78g/ml. The solution was a mixtu      Log On

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Question 161672: Working on Chemistry homework. Could not understand this problem in class, still don't understand. "The density of an antifreeze soltuion measured .78g/ml. The solution was a mixture of 40% water and 60% antifreeze compound. How many g of antifreeze compound are necessary to prepare 80.0 mL of antifreeze solution?" I tried setting up my equation a couple different ways and I am sure I did not get the right answer. I got 104 g/Antifreeze. Please help me figure out how to set up this equation!
Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
total mass of solution is 80(.78) or 62.4g

BY VOLUME
40% of 80 ml is 32 ml __ water is 1g/ml __ so 32g of water

62.4-32 or 30.4g of antifreeze


BY WEIGHT
60% of 62.4 is 37.4g of antifreeze