SOLUTION: Soybean meal is 14% protein, cornmeal is 7% protein. How many pounds of each should be mixed together in order to get 280 lb mixture that is 12% protein?
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Question 161488: Soybean meal is 14% protein, cornmeal is 7% protein. How many pounds of each should be mixed together in order to get 280 lb mixture that is 12% protein? Found 2 solutions by nerdybill, ankor@dixie-net.com:Answer by nerdybill(7384) (Show Source):
You can put this solution on YOUR website! Let x = amount of soybean meal
then because there is a total of 280 lbs:
280-x = amount of cornmeal
.
.14x + .07(280 - x) = .12(280)
.14x + 19.6 - .07x = 33.6
19.6 + .07x = 33.6
.07x = 14
x = 200 lbs (soybean meal)
.
cornmeal:
280-x = 280-200 = 80 lbs (cornmeal)
You can put this solution on YOUR website! Soybean meal is 14% protein, cornmeal is 7% protein. How many pounds of each
should be mixed together in order to get 280 lb mixture that is 12% protein?
:
Let x = amt of 14% protein
:
It states that the total mixture weight is 280 lb, therefore:
(280-x) = 7% protein
;
Write a decimal equivalent equation:
.14x + .07(280-x) = .12(280)
:
.14x + 19.6 - .07x = 33.6
:
.14x - .07x = 33.6 - 19.6
:
.07x = 14
x =
x = 200 lb of 14% protein, then 80 lb of 7% required
:
:
Check soltution in the original equation
.14(200) + .07(80) = .12(280)
28 + 5.6 = 33.6
