SOLUTION: A chemical engineer mixed two chemical solutions of different strenghts 30% and 50% of the chemical solutions respectively. How many millimiters of the 30% and 50% strenghts must b
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Question 160150: A chemical engineer mixed two chemical solutions of different strenghts 30% and 50% of the chemical solutions respectively. How many millimiters of the 30% and 50% strenghts must be used to produced a mixture of 50 millimeters that contains 42% of the chemical solutions? Answer by Fombitz(32388) (Show Source):
You can put this solution on YOUR website! Let T be the volume of 30% solution, F be the 50% solution.
Total volume
1.
Total concentration
2.
2.
Multiply eq.1 by -30 and add to eq. 2 and solve for F,
From 1,
1.
.
.
.
20mL of 30% solution, 30 mL of 50% solution.
