SOLUTION: A mixture containing 6% boric acid is to be mixed with 4 liters of a mixture which is 25% boric acid in order to obtain a solution which is 12% boric acid. How much of the 6% solut
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Question 159357: A mixture containing 6% boric acid is to be mixed with 4 liters of a mixture which is 25% boric acid in order to obtain a solution which is 12% boric acid. How much of the 6% solution must be used? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! A mixture containing 6% boric acid is to be mixed with 4 liters of a mixture which is 25% boric acid in order to obtain a solution which is 12% boric acid. How much of the 6% solution must be used?
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Acid EQUATIOn: 0.06x + 0.25*4 = 0.12(x+4)
6x + 100 = 12x + 48
6x = 52
x = 8 2/3 liters (amt. of 6% solution that must be added)
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Cheers,
Stan H.
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