SOLUTION: This problem has me stumped bcause I have 8 ounces already mixed and need to add to it to get 12 ounces. If I was just adding enough chocolate syrup to make it 42 percent, I would

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Question 15639: This problem has me stumped bcause I have 8 ounces already mixed and need to add to it to get 12 ounces. If I was just adding enough chocolate syrup to make it 42 percent, I would not be so confused. Here is the problem:
I want to make the perfect 12 ounce cup of chocolate milk. It requires that the mixture is 42% chocolate syrup. What I have right now is 8 ounces of milk/syrup mixture that I know contains 30% syrup. What must the syrup concentration be in the remaining mixture that I must add in order to achieve perfection?
Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
You'll need to set up the equation for the following:
8 oz of 30% syrup mixture + 4 oz of x% syrup mixture = 12 oz of 42% syrup mixture. Change the percents to decimals. The equation is:
8%280.3%29+%2B+4%28x%29+=+12%280.42%29 Simplify and solve for x.
2.4+%2B+4x+=+5.04 Subtract 2.4 from both sides.
4x+=+2.64 Divide both sides by 4.
x+=+0.66 Convert to a percent.
x = 66%