SOLUTION: A mechanic has found that a car with a 16-quart radiator has a 40% antifreeze mixture in the radiator. The mechanic has 70% antifreeze solution on hand. How much of the 40% solut
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Question 154401This question is from textbook intermediate algebra
: A mechanic has found that a car with a 16-quart radiator has a 40% antifreeze mixture in the radiator. The mechanic has 70% antifreeze solution on hand. How much of the 40% solution would the mechanic have to replace with the 70% solution to get the solution in the radiator up to 50%. This question is from textbook intermediate algebra
You can put this solution on YOUR website! mechanic has found that a car with a 16-quart radiator has a 40% antifreeze mixture in the radiator. The mechanic has 70% antifreeze solution on hand. How much of the 40% solution would the mechanic have to replace with the 70% solution to get the solution in the radiator up to 50%.
:
Let x = amt of 40% to be removed, and the amt of 70% to be added
:
.40(16-x) + .70x = .50(16)
;
6.5 - .4x + .7x = 8
:
-.4x + .7x = 8 - 6.4
:
.3x = 1.6
x =
x = 5 quarts of 40% removed
x = 5 quarts of 70% to be added
;
:
Check solution on a calc (16 - 5.33 = 10.67):
.4(10.67) + .7(5.33) = .5(16)
4.268 + 3.731 = 7.999 ~ 8, confirms our solution
