Question 150508This question is from textbook
: there were 3/4 as many women as there were men in a train yesterday. at the next station, 12 women and 6 men got in. as a result, there were 6/7 as many women as men on the train. how many men and women were in the train at first?
This question is from textbook
Answer by nerdybill(7384)   (Show Source):
You can put this solution on YOUR website! there were 3/4 as many women as there were men in a train yesterday. at the next station, 12 women and 6 men got in. as a result, there were 6/7 as many women as men on the train. how many men and women were in the train at first?
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Let M = # of men
(3/4)M = # of women
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(6/7)(M+6) = (3/4)M + 12
To get rid of all the denominators, multiply both sides by 28:
24(M+6) = 21M + 336
24M + 144 = 21M + 336
24M-21M = 336-144
3M = 192
M = 64 (Number of men in the train at first)
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(3/4)64 = 3(16) = 48 (Number of women in the train at first)
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