SOLUTION: a grocer mixes 12kg of one grade of beans with 10kg of another grade to obtain a blend worth 540 pesos. he then makes a second blend worth 610 pesos by mixing 8kg of the first grad
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Question 150505: a grocer mixes 12kg of one grade of beans with 10kg of another grade to obtain a blend worth 540 pesos. he then makes a second blend worth 610 pesos by mixing 8kg of the first grade with 15kg of the second grade. find the price per kilogram of each grade? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! a grocer mixes 12kg of one grade of beans with 10kg of another grade to obtain a blend worth 540 pesos. he then makes a second blend worth 610 pesos by mixing 8kg of the first grade with 15kg of the second grade. find the price per kilogram of each grade?
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Let "a" be the price of 1st bean and "b" be the price of 2nd bean.
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Value Equation: 12a + 10b = 540
Value Equation: 8a + 15b = 610
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Solve the system by substitution, elimination, or matrix to get:
a = 20 p
b = 30 p
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Cheers,
Stan H.
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