SOLUTION: please help me solve this problem, Ten gallons of a 30% acid solution is obtained by mixing a 20% solution with a 50% solution. How much of each must be used?

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Question 148043: please help me solve this problem,
Ten gallons of a 30% acid solution is obtained by mixing a 20% solution with a 50% solution. How much of each must be used?
Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
let x="gallons of 20%", so 10-x="gallons of 50%"

(20%)(x)+(50%)(10-x)=(30%)(10) Multiplying by 10 __ 2x+50-5x=30

subtracting 50 __ -3x=-20 __ dividing by -3 __ x=20/3

substituting __ 10-(20/3)=10/3