SOLUTION: Soybean meal is 12% protein; cornmeal is 6% protein. How many pounds of each should be mixed together in order to get 240-lb mixture that is 9% protein? How many pounds of the co
Algebra ->
Customizable Word Problem Solvers
-> Mixtures
-> SOLUTION: Soybean meal is 12% protein; cornmeal is 6% protein. How many pounds of each should be mixed together in order to get 240-lb mixture that is 9% protein? How many pounds of the co
Log On
Question 145685: Soybean meal is 12% protein; cornmeal is 6% protein. How many pounds of each should be mixed together in order to get 240-lb mixture that is 9% protein? How many pounds of the cornmeal should be in the mixture? How many pounds of the soybean meal should be in the mixture?
You can put this solution on YOUR website! Soybean meal is 12% protein; cornmeal is 6% protein. How many pounds of each should be mixed together in order to get 240-lb mixture that is 9% protein? How many pounds of the cornmeal should be in the mixture? How many pounds of the soybean meal should be in the mixture?
:
Since 9% is halfway between 12% and 6%, it would need 120 lb of each
:
However, here is the algebra procedure:
:
Let x = amt of soybean meal (12%)
:
It says the resulting amt = 240 lb, therefore:
(240-x) = amt of cornmeal (6%)
:
write the decimal equiv of the per cent protein equation:
.12x + .06(240-x) = .09(240)
:
.12x + 14.4 - .06x = 21.6
:
.12x - .06x = 21.6 - 14.4
:
.06x = 7.2
x =
x = 120 lb of soy meal
Then
240 - 120 = 120 lb of cornmeal
