Question 143892: How much pure water must be mixed with 6 pints of 90% developer to produce a mixture that is 17% developer? Found 2 solutions by stanbon, scott8148:Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! How much pure water must be mixed with 6 pints of 90% developer to produce a mixture that is 17% developer?
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active ingredient + active ingredient = active ingredient
0.9*6 + 0*x = 0.17(6+x)
5.4 = 1.02 + 0.17x
4.38 = 0.17x
x = 25.76 pints ( pure water must be mixed with the 90% developer)
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Cheers,
Stan H.
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