SOLUTION: A rocket is launched from atop a 102-foot cliff with an initial velocity of 158 ft/s. Substitute the values into the vertical motion formula h = -16t<sup>2</sup> + vt + c. Let h =

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Question 138056This question is from textbook Algebra 1
: A rocket is launched from atop a 102-foot cliff with an initial velocity of 158 ft/s. Substitute the values into the vertical motion formula h = -16t2 + vt + c. Let h = 0. Use the quadratic formula to find out how long after the rocket is launched it will hit the ground. Round to the nearest tenth of a second.
 This question is from textbook Algebra 1

Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
A rocket is launched from atop a 102-foot cliff with an initial velocity of 158
ft/s. Substitute the values into the vertical motion formula
h = -16t2 + vt + c. Let h = 0. Use the quadratic formula to find out how long
after the rocket is launched it will hit the ground. Round to the nearest tenth of a second.
:
Using the values given, the equation will be:
-16t^2 + 158t + 102 = 0
:
the quadratic formula:
x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
In this problem a = -16; b=158; c=102
t+=+%28-158+%2B-+sqrt%28158%5E2+-+4+%2A+-16+%2A+102+%29%29%2F%282%2A-16%29+
:
t+=+%28-158+%2B-+sqrt%2824964+-+%28-6528+%29%29%29%2F%28-32%29+
:
t+=+%28-158+%2B-+sqrt%2824964+%2B+6528+%29%29%2F%28-32%29+
;
t+=+%28-158+%2B-+sqrt%2831492%29%29%2F%28-32%29+
:
You can do the math here, you should get a positive solution of t = 10.483 sec