SOLUTION: What quantity of a 60% acid solution must be mixed with a 30% solution to produce 300mL of a 50% solution?

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Question 135455This question is from textbook
: What quantity of a 60% acid solution must be mixed with a 30% solution to produce 300mL of a 50% solution? This question is from textbook

Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
.6x+.3(300-x)=.5*300
.6x+90-.3x=150
.3x=150-90
.3x=60
x=60/.3
x=200 ml of 60% is used.
300-200=100 ml of 30% is used.
proof:
.6*200+.3*100=150
120+30=150
150=150