Question 13262: How much water should be added to 1 gallon of pure antifreeze to obtain a solution that is 60% antifreeze? Answer by rapaljer(4671) (Show Source):
You can put this solution on YOUR website! Let x = amount of water to be added with 0% antifreeze
1 = amount of pure antifreeze at 100%
x+1 = amount of the mixture at 60% antifreeze
1 = .60x + .60
Subtract .60 from each side:
1-.60 = .60x
.40 = .60x
Divide both sides by .60:
gallon.
Check: Total antifreeze = 1 gallon in total mixture of 1 + 2/3 gallon = 5/3 gallons. 1 gallon divided by 5/3 equals 3/5 which is 60%. It checks.
