SOLUTION: Please help me. I have done this and it is wrong. I am grateful for any help. Soymeal is 12% protein and cornmeal is 6%. How many pounds of each should be mixed together to get 2

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Question 127170: Please help me. I have done this and it is wrong. I am grateful for any help.
Soymeal is 12% protein and cornmeal is 6%. How many pounds of each should be mixed together to get 240 pound mixture that is 7% protein? Thanks so much...
Found 2 solutions by ankor@dixie-net.com, josmiceli:
Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website!
Soymeal is 12% protein and cornmeal is 6%. How many pounds of each should be mixed together to get 240 pound mixture that is 7% protein?
:
Let x = amt of Soymeal required
The total is given as 240 lb, therefore:
(240-x) = amt of cornmeal required
:
.12x + .06(240-x) = .07(240)
:
.12x + 14.4 - .06x = 16.8
:
.12x - .06x = 16.8 - 14.4
:
.06x = 2.4
x =
x = 40 lb of Soymeal
Then
240 - 40 = 200 lb of corn meal
;
:
Check solution in the equation
.12(40) + .06(200) = .07(240)
4.8 + 12 = 16.8 confirms our solutions

Answer by josmiceli(19441) (Show Source):
You can put this solution on YOUR website!
(protein in soymeal) + (protein in cornmeal) divided by
(soymeal + cornmeal) = % protein in mixture
Call amount of soymeal needed
Call amount of cornmeal needed

40 pounds of soymeal should be mixed with 200 pounds of cornmeal
check answer

OK